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13402343303 = 89241624847
BaseRepresentation
bin11000111101101011…
…11000011110000111
31021121000212120201022
430132311320132013
5204421444441203
610053522421355
7653060016116
oct143665703607
937530776638
1013402343303
115758300988
12272050185b
131357853a6b
14911d7dc7d
15536929a38
hex31ed78787

13402343303 has 8 divisors (see below), whose sum is σ = 13609189440. Its totient is φ = 13196747520.

The previous prime is 13402343293. The next prime is 13402343323. The reversal of 13402343303 is 30334320431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402343303 - 24 = 13402343287 is a prime.

It is a super-2 number, since 2×134023433032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402343323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 290975 + ... + 333872.

It is an arithmetic number, because the mean of its divisors is an integer number (1701148680).

Almost surely, 213402343303 is an apocalyptic number.

13402343303 is a deficient number, since it is larger than the sum of its proper divisors (206846137).

13402343303 is an equidigital number, since it uses as much as digits as its factorization.

13402343303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 625177.

The product of its (nonzero) digits is 7776, while the sum is 26.

Adding to 13402343303 its reverse (30334320431), we get a palindrome (43736663734).

The spelling of 13402343303 in words is "thirteen billion, four hundred two million, three hundred forty-three thousand, three hundred three".

Divisors: 1 89 241 21449 624847 55611383 150588127 13402343303