Base | Representation |
---|---|
bin | 11000111101101011… |
… | …11011101100010101 |
3 | 1021121000220020211010 |
4 | 30132311323230111 |
5 | 204422000402001 |
6 | 10053523002433 |
7 | 653060102442 |
oct | 143665735425 |
9 | 37530806733 |
10 | 13402356501 |
11 | 575830a896 |
12 | 2720509419 |
13 | 1357859a81 |
14 | 911d849c9 |
15 | 53692d8d6 |
hex | 31ed7bb15 |
13402356501 has 4 divisors (see below), whose sum is σ = 17869808672. Its totient is φ = 8934904332.
The previous prime is 13402356481. The next prime is 13402356523. The reversal of 13402356501 is 10565320431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13402356501 - 25 = 13402356469 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13402356551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233726081 + ... + 2233726086.
It is an arithmetic number, because the mean of its divisors is an integer number (4467452168).
Almost surely, 213402356501 is an apocalyptic number.
It is an amenable number.
13402356501 is a deficient number, since it is larger than the sum of its proper divisors (4467452171).
13402356501 is an equidigital number, since it uses as much as digits as its factorization.
13402356501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4467452170.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 13402356501 its reverse (10565320431), we get a palindrome (23967676932).
The spelling of 13402356501 in words is "thirteen billion, four hundred two million, three hundred fifty-six thousand, five hundred one".
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