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134024222201 is a prime number
BaseRepresentation
bin111110011010001110…
…1110101010111111001
3110210221101012220200112
41330310131311113321
54143440200102301
6141323032114105
712453150043412
oct1746435652771
9423841186615
10134024222201
11519261a7901
1221b84535935
13c83b8273bc
1466b5b26809
1537462c09bb
hex1f347755f9

134024222201 has 2 divisors, whose sum is σ = 134024222202. Its totient is φ = 134024222200.

The previous prime is 134024222183. The next prime is 134024222203. The reversal of 134024222201 is 102222420431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69261606976 + 64762615225 = 263176^2 + 254485^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134024222201 is a prime.

Together with 134024222203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (134024222203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012111100 + 67012111101.

It is an arithmetic number, because the mean of its divisors is an integer number (67012111101).

Almost surely, 2134024222201 is an apocalyptic number.

It is an amenable number.

134024222201 is a deficient number, since it is larger than the sum of its proper divisors (1).

134024222201 is an equidigital number, since it uses as much as digits as its factorization.

134024222201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 134024222201 its reverse (102222420431), we get a palindrome (236246642632).

The spelling of 134024222201 in words is "one hundred thirty-four billion, twenty-four million, two hundred twenty-two thousand, two hundred one".