Base | Representation |
---|---|
bin | 11000111101101101… |
… | …00000000010001101 |
3 | 1021121001011211000022 |
4 | 30132312200002031 |
5 | 204422020132412 |
6 | 10053530111525 |
7 | 653061262433 |
oct | 143666400215 |
9 | 37531154008 |
10 | 13402505357 |
11 | 575840170a |
12 | 272057b5a5 |
13 | 13578ac757 |
14 | 911dc2d53 |
15 | 53695ca72 |
hex | 31eda008d |
13402505357 has 2 divisors, whose sum is σ = 13402505358. Its totient is φ = 13402505356.
The previous prime is 13402505321. The next prime is 13402505359. The reversal of 13402505357 is 75350520431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12892694116 + 509811241 = 113546^2 + 22579^2 .
It is a cyclic number.
It is not a de Polignac number, because 13402505357 - 210 = 13402504333 is a prime.
Together with 13402505359, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13402505359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701252678 + 6701252679.
It is an arithmetic number, because the mean of its divisors is an integer number (6701252679).
Almost surely, 213402505357 is an apocalyptic number.
It is an amenable number.
13402505357 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402505357 is an equidigital number, since it uses as much as digits as its factorization.
13402505357 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63000, while the sum is 35.
The spelling of 13402505357 in words is "thirteen billion, four hundred two million, five hundred five thousand, three hundred fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.156 sec. • engine limits •