Base | Representation |
---|---|
bin | 111110011010010110… |
… | …0110001110111100000 |
3 | 110210221122120221220012 |
4 | 1330310230301313200 |
5 | 4143442200440000 |
6 | 141323252104052 |
7 | 12453225251516 |
oct | 1746454616740 |
9 | 423848527805 |
10 | 134028140000 |
11 | 51928433357 |
12 | 21b85905028 |
13 | c83c599721 |
14 | 66b64664b6 |
15 | 37467e6735 |
hex | 1f34b31de0 |
134028140000 has 240 divisors, whose sum is σ = 346290714000. Its totient is φ = 50975232000.
The previous prime is 134028139939. The next prime is 134028140017. The reversal of 134028140000 is 41820431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 38858276 + ... + 38861724.
It is an arithmetic number, because the mean of its divisors is an integer number (1442877975).
Almost surely, 2134028140000 is an apocalyptic number.
134028140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134028140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173145357000).
134028140000 is an abundant number, since it is smaller than the sum of its proper divisors (212262574000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134028140000 is an equidigital number, since it uses as much as digits as its factorization.
134028140000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3575 (or 3552 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 134028140000 its reverse (41820431), we get a palindrome (134069960431).
The spelling of 134028140000 in words is "one hundred thirty-four billion, twenty-eight million, one hundred forty thousand".
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