Base | Representation |
---|---|
bin | 11000111101110001… |
… | …10010000010101011 |
3 | 1021121002022012101011 |
4 | 30132320302002223 |
5 | 204422143302103 |
6 | 10053551004351 |
7 | 653066333134 |
oct | 143670620253 |
9 | 37532265334 |
10 | 13403103403 |
11 | 575877aa68 |
12 | 27208096b7 |
13 | 1357a5ba21 |
14 | 9120dac8b |
15 | 536a29d6d |
hex | 31ee320ab |
13403103403 has 2 divisors, whose sum is σ = 13403103404. Its totient is φ = 13403103402.
The previous prime is 13403103361. The next prime is 13403103457. The reversal of 13403103403 is 30430130431.
It is a happy number.
13403103403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13403103403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13403103463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701551701 + 6701551702.
It is an arithmetic number, because the mean of its divisors is an integer number (6701551702).
Almost surely, 213403103403 is an apocalyptic number.
13403103403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13403103403 is an equidigital number, since it uses as much as digits as its factorization.
13403103403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 13403103403 its reverse (30430130431), we get a palindrome (43833233834).
The spelling of 13403103403 in words is "thirteen billion, four hundred three million, one hundred three thousand, four hundred three".
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