Base | Representation |
---|---|
bin | 11000111101110001… |
… | …11100100000001011 |
3 | 1021121002101101011010 |
4 | 30132320330200023 |
5 | 204422201140001 |
6 | 10053551535003 |
7 | 653066602065 |
oct | 143670744013 |
9 | 37532341133 |
10 | 13403146251 |
11 | 57587aa180 |
12 | 272082a463 |
13 | 1357a75391 |
14 | 91210c735 |
15 | 536a378d6 |
hex | 31ee3c80b |
13403146251 has 16 divisors (see below), whose sum is σ = 19499397120. Its totient is φ = 8121489120.
The previous prime is 13403146213. The next prime is 13403146291. The reversal of 13403146251 is 15264130431.
13403146251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13403146251 - 211 = 13403144203 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13403146291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137910 + ... + 214068.
It is an arithmetic number, because the mean of its divisors is an integer number (1218712320).
Almost surely, 213403146251 is an apocalyptic number.
13403146251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13403146251 is a deficient number, since it is larger than the sum of its proper divisors (6096250869).
13403146251 is a wasteful number, since it uses less digits than its factorization.
13403146251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81506.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 13403146251 its reverse (15264130431), we get a palindrome (28667276682).
The spelling of 13403146251 in words is "thirteen billion, four hundred three million, one hundred forty-six thousand, two hundred fifty-one".
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