Search a number
-
+
13403244213104 = 24837702763319
BaseRepresentation
bin1100001100001010111110…
…0111000011001101110000
31202110100010010122000000012
43003002233213003031300
53224044321004304404
644301210531314052
72552231613015554
oct303025747031560
952410103560005
1013403244213104
1142a8313a33449
12160577b44b928
13762bc7475685
14344a13001864
151839b0cb3a6e
hexc30af9c3370

13403244213104 has 10 divisors (see below), whose sum is σ = 25968785662920. Its totient is φ = 6701622106544.

The previous prime is 13403244213067. The next prime is 13403244213137. The reversal of 13403244213104 is 40131244230431.

It is a super-2 number, since 2×134032442131042 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 418851381644 + ... + 418851381675.

It is an arithmetic number, because the mean of its divisors is an integer number (2596878566292).

Almost surely, 213403244213104 is an apocalyptic number.

It is an amenable number.

13403244213104 is a deficient number, since it is larger than the sum of its proper divisors (12565541449816).

13403244213104 is an equidigital number, since it uses as much as digits as its factorization.

13403244213104 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 837702763327 (or 837702763321 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13403244213104 its reverse (40131244230431), we get a palindrome (53534488443535).

The spelling of 13403244213104 in words is "thirteen trillion, four hundred three billion, two hundred forty-four million, two hundred thirteen thousand, one hundred four".

Divisors: 1 2 4 8 16 837702763319 1675405526638 3350811053276 6701622106552 13403244213104