1340330213133 has 12 divisors (see below), whose sum is σ = 1940268931068. Its totient is φ = 891598213440.

The previous prime is 1340330213093. The next prime is 1340330213149. The reversal of 1340330213133 is 3313120330431.

1340330213133 is a `hidden beast` number, since 1 + 3 + 40 + 3 + 302 + 1 + 313 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 649574745444 + 690755467689 = 805962^2 + 831117^2 .

It is not a de Polignac number, because 1340330213133 - 2⁹ = 1340330212621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340330213097 and 1340330213106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340330213933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 162934158 + ... + 162942383.

It is an arithmetic number, because the mean of its divisors is an integer number (161689077589).

Almost surely, 2^{1340330213133} is an apocalyptic number.

It is an amenable number.

1340330213133 is a deficient number, since it is larger than the sum of its proper divisors (599938717935).

1340330213133 is a wasteful number, since it uses less digits than its factorization.

1340330213133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 325877004 (or 325877001 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 27.

Adding to 1340330213133 its reverse (3313120330431), we get a palindrome (4653450543564).

The spelling of 1340330213133 in words is "one trillion, three hundred forty billion, three hundred thirty million, two hundred thirteen thousand, one hundred thirty-three".