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1340337674369 is a prime number
BaseRepresentation
bin10011100000010010010…
…110011101100010000001
311202010122102210121212202
4103200102112131202001
5133430002421034434
62503424224002545
7165556550152511
oct23402226354201
94663572717782
101340337674369
11477485746a61
12197924460455
1399516108905
1448c30935841
1524cea3ada7e
hex1381259d881

1340337674369 has 2 divisors, whose sum is σ = 1340337674370. Its totient is φ = 1340337674368.

The previous prime is 1340337674317. The next prime is 1340337674371. The reversal of 1340337674369 is 9634767330431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1258491330625 + 81846343744 = 1121825^2 + 286088^2 .

It is an emirp because it is prime and its reverse (9634767330431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340337674369 - 28 = 1340337674113 is a prime.

It is a super-2 number, since 2×13403376743692 (a number of 25 digits) contains 22 as substring.

Together with 1340337674371, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1340337674309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670168837184 + 670168837185.

It is an arithmetic number, because the mean of its divisors is an integer number (670168837185).

Almost surely, 21340337674369 is an apocalyptic number.

It is an amenable number.

1340337674369 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340337674369 is an equidigital number, since it uses as much as digits as its factorization.

1340337674369 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20575296, while the sum is 56.

The spelling of 1340337674369 in words is "one trillion, three hundred forty billion, three hundred thirty-seven million, six hundred seventy-four thousand, three hundred sixty-nine".