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1340340101431 is a prime number
BaseRepresentation
bin10011100000010010011…
…111101110000100110111
311202010122121100221011221
4103200102133232010313
5133430004031221211
62503424352011211
7165556606611502
oct23402237560467
94663577327157
101340340101431
114774870544a1
12197925230b07
1399516778546
1448c30da8139
1524cea6dcc71
hex138127ee137

1340340101431 has 2 divisors, whose sum is σ = 1340340101432. Its totient is φ = 1340340101430.

The previous prime is 1340340101407. The next prime is 1340340101437. The reversal of 1340340101431 is 1341010430431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340340101431 - 235 = 1305980363063 is a prime.

It is a super-2 number, since 2×13403401014312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340340101396 and 1340340101405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340340101437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670170050715 + 670170050716.

It is an arithmetic number, because the mean of its divisors is an integer number (670170050716).

Almost surely, 21340340101431 is an apocalyptic number.

1340340101431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340340101431 is an equidigital number, since it uses as much as digits as its factorization.

1340340101431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1340340101431 its reverse (1341010430431), we get a palindrome (2681350531862).

The spelling of 1340340101431 in words is "one trillion, three hundred forty billion, three hundred forty million, one hundred one thousand, four hundred thirty-one".