Search a number
-
+
1340344140423 = 3446781380141
BaseRepresentation
bin10011100000010010101…
…111001000001010000111
311202010122212222010122020
4103200102233020022013
5133430011044443143
62503425014334223
7165556656133131
oct23402257101207
94663585863566
101340344140423
11477489363002
1219792665a373
1399517560a92
1448c3173a051
1524ceac39883
hex13812bc8287

1340344140423 has 4 divisors (see below), whose sum is σ = 1787125520568. Its totient is φ = 893562760280.

The previous prime is 1340344140403. The next prime is 1340344140437. The reversal of 1340344140423 is 3240414430431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340344140423 - 217 = 1340344009351 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340344140403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223390690068 + ... + 223390690073.

It is an arithmetic number, because the mean of its divisors is an integer number (446781380142).

Almost surely, 21340344140423 is an apocalyptic number.

1340344140423 is a deficient number, since it is larger than the sum of its proper divisors (446781380145).

1340344140423 is an equidigital number, since it uses as much as digits as its factorization.

1340344140423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446781380144.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 1340344140423 its reverse (3240414430431), we get a palindrome (4580758570854).

The spelling of 1340344140423 in words is "one trillion, three hundred forty billion, three hundred forty-four million, one hundred forty thousand, four hundred twenty-three".

Divisors: 1 3 446781380141 1340344140423