Base | Representation |
---|---|
bin | 11000111101110100… |
… | …01100101100101101 |
3 | 1021121010000001202010 |
4 | 30132322030230231 |
5 | 204422242142413 |
6 | 10054002551433 |
7 | 653102440545 |
oct | 143672145455 |
9 | 37533001663 |
10 | 13403474733 |
11 | 5758a03a50 |
12 | 2720968579 |
13 | 1357b5ba4c |
14 | 912196325 |
15 | 536a9edc3 |
hex | 31ee8cb2d |
13403474733 has 32 divisors (see below), whose sum is σ = 20533865472. Its totient is φ = 7697465600.
The previous prime is 13403474699. The next prime is 13403474761. The reversal of 13403474733 is 33747430431.
It is not a de Polignac number, because 13403474733 - 28 = 13403474477 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13403474691 and 13403474700.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13403474783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1308 + ... + 163733.
It is an arithmetic number, because the mean of its divisors is an integer number (641683296).
Almost surely, 213403474733 is an apocalyptic number.
It is an amenable number.
13403474733 is a deficient number, since it is larger than the sum of its proper divisors (7130390739).
13403474733 is a wasteful number, since it uses less digits than its factorization.
13403474733 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 165185.
The product of its (nonzero) digits is 254016, while the sum is 39.
The spelling of 13403474733 in words is "thirteen billion, four hundred three million, four hundred seventy-four thousand, seven hundred thirty-three".
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