Base | Representation |
---|---|
bin | 10011100000010110010… |
… | …000001101011000011111 |
3 | 11202010210222222211122011 |
4 | 103200112100031120133 |
5 | 133430121201103343 |
6 | 2503434523132051 |
7 | 165561303510643 |
oct | 23402620153037 |
9 | 4663728884564 |
10 | 1340403144223 |
11 | 4775096a3480 |
12 | 197942374027 |
13 | 9952684c480 |
14 | 48c394d8c23 |
15 | 24d00ee229d |
hex | 1381640d61f |
1340403144223 has 32 divisors (see below), whose sum is σ = 1590037827840. Its totient is φ = 1113894063360.
The previous prime is 1340403144221. The next prime is 1340403144251. The reversal of 1340403144223 is 3224413040431.
It is not a de Polignac number, because 1340403144223 - 21 = 1340403144221 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340403144221) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 46179211 + ... + 46208227.
It is an arithmetic number, because the mean of its divisors is an integer number (49688682120).
Almost surely, 21340403144223 is an apocalyptic number.
1340403144223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1340403144223 is a deficient number, since it is larger than the sum of its proper divisors (249634683617).
1340403144223 is a wasteful number, since it uses less digits than its factorization.
1340403144223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32167.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1340403144223 its reverse (3224413040431), we get a palindrome (4564816184654).
The spelling of 1340403144223 in words is "one trillion, three hundred forty billion, four hundred three million, one hundred forty-four thousand, two hundred twenty-three".
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