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134040615155 = 526808123031
BaseRepresentation
bin111110011010101110…
…0010111100011110011
3110210222112001202120222
41330311130113203303
54144003344141110
6141324415323255
712453436300316
oct1746534274363
9423875052528
10134040615155
11519344840a7
1221b89b2052b
13c842046a85
1466b7d9297d
15374795cc55
hex1f357178f3

134040615155 has 4 divisors (see below), whose sum is σ = 160848738192. Its totient is φ = 107232492120.

The previous prime is 134040615127. The next prime is 134040615167. The reversal of 134040615155 is 551516040431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 134040615155 - 26 = 134040615091 is a prime.

It is a super-2 number, since 2×1340406151552 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13404061511 + ... + 13404061520.

It is an arithmetic number, because the mean of its divisors is an integer number (40212184548).

Almost surely, 2134040615155 is an apocalyptic number.

134040615155 is a deficient number, since it is larger than the sum of its proper divisors (26808123037).

134040615155 is an equidigital number, since it uses as much as digits as its factorization.

134040615155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26808123036.

The product of its (nonzero) digits is 36000, while the sum is 35.

Adding to 134040615155 its reverse (551516040431), we get a palindrome (685556655586).

The spelling of 134040615155 in words is "one hundred thirty-four billion, forty million, six hundred fifteen thousand, one hundred fifty-five".

Divisors: 1 5 26808123031 134040615155