13404214113433 has 8 divisors (see below), whose sum is σ = 15747608189376. Its totient is φ = 11248291563600.

The previous prime is 13404214113419. The next prime is 13404214113443. The reversal of 13404214113433 is 33431141240431.

13404214113433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-13404214113433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13404214113443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46867881373 + ... + 46867881658.

It is an arithmetic number, because the mean of its divisors is an integer number (1968451023672).

Almost surely, 2^{13404214113433} is an apocalyptic number.

13404214113433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13404214113433 is a deficient number, since it is larger than the sum of its proper divisors (2343394075943).

13404214113433 is a wasteful number, since it uses less digits than its factorization.

13404214113433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93735763055.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 13404214113433 its reverse (33431141240431), we get a palindrome (46835355353864).

The spelling of 13404214113433 in words is "thirteen trillion, four hundred four billion, two hundred fourteen million, one hundred thirteen thousand, four hundred thirty-three".