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1340424004315 = 51197125099223
BaseRepresentation
bin10011100000010111011…
…111110010001011011011
311202010212110020122022011
4103200113133302023123
5133430142021114230
62503440550210351
7165561646021354
oct23402737621333
94663773218264
101340424004315
1147751a450a20
121979493539b7
139952ac74216
1448c3c1a8d2b
1524d02c62e2a
hex138177f22db

1340424004315 has 16 divisors (see below), whose sum is σ = 1756544092416. Its totient is φ = 973849813600.

The previous prime is 1340424004273. The next prime is 1340424004327. The reversal of 1340424004315 is 5134004240431.

It is not a de Polignac number, because 1340424004315 - 227 = 1340289786587 is a prime.

It is a super-2 number, since 2×13404240043152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12496207 + ... + 12603016.

It is an arithmetic number, because the mean of its divisors is an integer number (109784005776).

Almost surely, 21340424004315 is an apocalyptic number.

1340424004315 is a deficient number, since it is larger than the sum of its proper divisors (416120088101).

1340424004315 is a wasteful number, since it uses less digits than its factorization.

1340424004315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25100210.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 1340424004315 its reverse (5134004240431), we get a palindrome (6474428244746).

The spelling of 1340424004315 in words is "one trillion, three hundred forty billion, four hundred twenty-four million, four thousand, three hundred fifteen".

Divisors: 1 5 11 55 971 4855 10681 53405 25099223 125496115 276091453 1380457265 24371345533 121856727665 268084800863 1340424004315