Base | Representation |
---|---|
bin | 10011100000010111011… |
… | …111110010001011011011 |
3 | 11202010212110020122022011 |
4 | 103200113133302023123 |
5 | 133430142021114230 |
6 | 2503440550210351 |
7 | 165561646021354 |
oct | 23402737621333 |
9 | 4663773218264 |
10 | 1340424004315 |
11 | 47751a450a20 |
12 | 1979493539b7 |
13 | 9952ac74216 |
14 | 48c3c1a8d2b |
15 | 24d02c62e2a |
hex | 138177f22db |
1340424004315 has 16 divisors (see below), whose sum is σ = 1756544092416. Its totient is φ = 973849813600.
The previous prime is 1340424004273. The next prime is 1340424004327. The reversal of 1340424004315 is 5134004240431.
It is not a de Polignac number, because 1340424004315 - 227 = 1340289786587 is a prime.
It is a super-2 number, since 2×13404240043152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12496207 + ... + 12603016.
It is an arithmetic number, because the mean of its divisors is an integer number (109784005776).
Almost surely, 21340424004315 is an apocalyptic number.
1340424004315 is a deficient number, since it is larger than the sum of its proper divisors (416120088101).
1340424004315 is a wasteful number, since it uses less digits than its factorization.
1340424004315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25100210.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 1340424004315 its reverse (5134004240431), we get a palindrome (6474428244746).
The spelling of 1340424004315 in words is "one trillion, three hundred forty billion, four hundred twenty-four million, four thousand, three hundred fifteen".
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