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134042431353402 = 2311132319743978541
BaseRepresentation
bin11110011110100100101111…
…100000010111001000111010
3122120121022221111210002001110
4132132210233200113020322
5120032122344411302102
61153030124243101150
740143150256235355
oct3636445740271072
9576538844702043
10134042431353402
113978a092024710
121304a3a30717b6
1359a41bb078b10
14251598c96b29c
151076b4070686c
hex79e92f81723a

134042431353402 has 256 divisors, whose sum is σ = 331071344271360. Its totient is φ = 35600410137600.

The previous prime is 134042431353353. The next prime is 134042431353419. The reversal of 134042431353402 is 204353134240431.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1706616252 + ... + 1706694792.

It is an arithmetic number, because the mean of its divisors is an integer number (1293247438560).

Almost surely, 2134042431353402 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134042431353402, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (165535672135680).

134042431353402 is an abundant number, since it is smaller than the sum of its proper divisors (197028912917958).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134042431353402 is a wasteful number, since it uses less digits than its factorization.

134042431353402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79229.

The product of its (nonzero) digits is 414720, while the sum is 39.

Adding to 134042431353402 its reverse (204353134240431), we get a palindrome (338395565593833).

The spelling of 134042431353402 in words is "one hundred thirty-four trillion, forty-two billion, four hundred thirty-one million, three hundred fifty-three thousand, four hundred two".