Base | Representation |
---|---|
bin | 11000111101111010… |
… | …01001001000000011 |
3 | 1021121011110021110020 |
4 | 30132331021020003 |
5 | 204422441342111 |
6 | 10054031304523 |
7 | 653112133644 |
oct | 143675111003 |
9 | 37534407406 |
10 | 13404246531 |
11 | 57593908a5 |
12 | 272107b143 |
13 | 135806c130 |
14 | 9123176cb |
15 | 536ba3906 |
hex | 31ef49203 |
13404246531 has 8 divisors (see below), whose sum is σ = 19247123280. Its totient is φ = 8248767072.
The previous prime is 13404246473. The next prime is 13404246637. The reversal of 13404246531 is 13564240431.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13404246531 - 29 = 13404246019 is a prime.
It is a super-2 number, since 2×134042465312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13404246492 and 13404246501.
It is not an unprimeable number, because it can be changed into a prime (13404246731) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 171849276 + ... + 171849353.
It is an arithmetic number, because the mean of its divisors is an integer number (2405890410).
Almost surely, 213404246531 is an apocalyptic number.
13404246531 is a deficient number, since it is larger than the sum of its proper divisors (5842876749).
13404246531 is a wasteful number, since it uses less digits than its factorization.
13404246531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343698645.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 13404246531 its reverse (13564240431), we get a palindrome (26968486962).
The spelling of 13404246531 in words is "thirteen billion, four hundred four million, two hundred forty-six thousand, five hundred thirty-one".
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