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13404246531 = 313343698629
BaseRepresentation
bin11000111101111010…
…01001001000000011
31021121011110021110020
430132331021020003
5204422441342111
610054031304523
7653112133644
oct143675111003
937534407406
1013404246531
1157593908a5
12272107b143
13135806c130
149123176cb
15536ba3906
hex31ef49203

13404246531 has 8 divisors (see below), whose sum is σ = 19247123280. Its totient is φ = 8248767072.

The previous prime is 13404246473. The next prime is 13404246637. The reversal of 13404246531 is 13564240431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13404246531 - 29 = 13404246019 is a prime.

It is a super-2 number, since 2×134042465312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13404246492 and 13404246501.

It is not an unprimeable number, because it can be changed into a prime (13404246731) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 171849276 + ... + 171849353.

It is an arithmetic number, because the mean of its divisors is an integer number (2405890410).

Almost surely, 213404246531 is an apocalyptic number.

13404246531 is a deficient number, since it is larger than the sum of its proper divisors (5842876749).

13404246531 is a wasteful number, since it uses less digits than its factorization.

13404246531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 343698645.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 13404246531 its reverse (13564240431), we get a palindrome (26968486962).

The spelling of 13404246531 in words is "thirteen billion, four hundred four million, two hundred forty-six thousand, five hundred thirty-one".

Divisors: 1 3 13 39 343698629 1031095887 4468082177 13404246531