Base | Representation |
---|---|
bin | 11000111101111011… |
… | …01111000110110111 |
3 | 1021121011202011212011 |
4 | 30132331233012313 |
5 | 204423011331403 |
6 | 10054034505051 |
7 | 653113352341 |
oct | 143675570667 |
9 | 37534664764 |
10 | 13404402103 |
11 | 5759487774 |
12 | 2721135187 |
13 | 13580c4ba1 |
14 | 912358291 |
15 | 536bd4a6d |
hex | 31ef6f1b7 |
13404402103 has 4 divisors (see below), whose sum is σ = 13462936840. Its totient is φ = 13345867368.
The previous prime is 13404402061. The next prime is 13404402133. The reversal of 13404402103 is 30120440431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30120440431 = 191 ⋅157698641.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13404402103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13404402133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29267025 + ... + 29267482.
It is an arithmetic number, because the mean of its divisors is an integer number (3365734210).
Almost surely, 213404402103 is an apocalyptic number.
13404402103 is a deficient number, since it is larger than the sum of its proper divisors (58534737).
13404402103 is an equidigital number, since it uses as much as digits as its factorization.
13404402103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58534736.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 13404402103 its reverse (30120440431), we get a palindrome (43524842534).
The spelling of 13404402103 in words is "thirteen billion, four hundred four million, four hundred two thousand, one hundred three".
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