13404506064631 has 32 divisors (see below), whose sum is σ = 15737743929600. Its totient is φ = 11282118151680.

The previous prime is 13404506064623. The next prime is 13404506064683. The reversal of 13404506064631 is 13646060540431.

It is a cyclic number.

It is not a de Polignac number, because 13404506064631 - 2³ = 13404506064623 is a prime.

It is a super-2 number, since 2×13404506064631² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13404506064601) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 467656 + ... + 5198818.

It is an arithmetic number, because the mean of its divisors is an integer number (491804497800).

Almost surely, 2^{13404506064631} is an apocalyptic number.

13404506064631 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13404506064631 is a deficient number, since it is larger than the sum of its proper divisors (2333237864969).

13404506064631 is a wasteful number, since it uses less digits than its factorization.

13404506064631 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4731439.

The product of its (nonzero) digits is 622080, while the sum is 43.

The spelling of 13404506064631 in words is "thirteen trillion, four hundred four billion, five hundred six million, sixty-four thousand, six hundred thirty-one".