Base | Representation |
---|---|
bin | 10011100000011001010… |
… | …010011000010101011101 |
3 | 11202010221112202212101220 |
4 | 103200121102120111131 |
5 | 133430222213420041 |
6 | 2503443542123553 |
7 | 165562462246530 |
oct | 23403122302535 |
9 | 4663845685356 |
10 | 1340454045021 |
11 | 4775353a9a53 |
12 | 1979574205b9 |
13 | 995342618a0 |
14 | 48c42188a17 |
15 | 24d056e8d66 |
hex | 1381949855d |
1340454045021 has 32 divisors (see below), whose sum is σ = 2200951216128. Its totient is φ = 706656761280.
The previous prime is 1340454044999. The next prime is 1340454045071. The reversal of 1340454045021 is 1205404540431.
It is a happy number.
It is not a de Polignac number, because 1340454045021 - 25 = 1340454044989 is a prime.
It is a super-2 number, since 2×13404540450212 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340454045071) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 885985 + ... + 1861686.
It is an arithmetic number, because the mean of its divisors is an integer number (68779725504).
Almost surely, 21340454045021 is an apocalyptic number.
It is an amenable number.
1340454045021 is a deficient number, since it is larger than the sum of its proper divisors (860497171107).
1340454045021 is a wasteful number, since it uses less digits than its factorization.
1340454045021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2749481.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 1340454045021 its reverse (1205404540431), we get a palindrome (2545858585452).
The spelling of 1340454045021 in words is "one trillion, three hundred forty billion, four hundred fifty-four million, forty-five thousand, twenty-one".
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