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134048103310 = 25112942021349
BaseRepresentation
bin111110011010111100…
…0111011101110001110
3110211000001011012102001
41330311320323232032
54144012303301220
6141325244022514
712453560035552
oct1746570735616
9424001135361
10134048103310
1151938729060
1221b90531a3a
13c843769234
1466b8d81862
15374843b80a
hex1f35e3bb8e

134048103310 has 32 divisors (see below), whose sum is σ = 272298348000. Its totient is φ = 47063909760.

The previous prime is 134048103271. The next prime is 134048103331. The reversal of 134048103310 is 13301840431.

It is a super-2 number, since 2×1340481033102 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21007485 + ... + 21013864.

It is an arithmetic number, because the mean of its divisors is an integer number (8509323375).

Almost surely, 2134048103310 is an apocalyptic number.

134048103310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134048103310 is an abundant number, since it is smaller than the sum of its proper divisors (138250244690).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134048103310 is a wasteful number, since it uses less digits than its factorization.

134048103310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42021396.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 134048103310 its reverse (13301840431), we get a palindrome (147349943741).

The spelling of 134048103310 in words is "one hundred thirty-four billion, forty-eight million, one hundred three thousand, three hundred ten".

Divisors: 1 2 5 10 11 22 29 55 58 110 145 290 319 638 1595 3190 42021349 84042698 210106745 420213490 462234839 924469678 1218619121 2311174195 2437238242 4622348390 6093095605 12186191210 13404810331 26809620662 67024051655 134048103310