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134048111047 is a prime number
BaseRepresentation
bin111110011010111100…
…0111101100111000111
3110211000001011121000121
41330311320331213013
54144012304023142
6141325244122411
712453560100244
oct1746570754707
9424001147017
10134048111047
1151938733954
1221b90536407
13c84376c906
1466b8d845cb
15374843dc67
hex1f35e3d9c7

134048111047 has 2 divisors, whose sum is σ = 134048111048. Its totient is φ = 134048111046.

The previous prime is 134048110993. The next prime is 134048111081. The reversal of 134048111047 is 740111840431.

It is an a-pointer prime, because the next prime (134048111081) can be obtained adding 134048111047 to its sum of digits (34).

It is a strong prime.

It is an emirp because it is prime and its reverse (740111840431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134048111047 - 227 = 133913893319 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134048112047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67024055523 + 67024055524.

It is an arithmetic number, because the mean of its divisors is an integer number (67024055524).

Almost surely, 2134048111047 is an apocalyptic number.

134048111047 is a deficient number, since it is larger than the sum of its proper divisors (1).

134048111047 is an equidigital number, since it uses as much as digits as its factorization.

134048111047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 34.

Adding to 134048111047 its reverse (740111840431), we get a palindrome (874159951478).

The spelling of 134048111047 in words is "one hundred thirty-four billion, forty-eight million, one hundred eleven thousand, forty-seven".