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134048111057 = 7143891330859
BaseRepresentation
bin111110011010111100…
…0111101100111010001
3110211000001011121000222
41330311320331213101
54144012304023212
6141325244122425
712453560100260
oct1746570754721
9424001147028
10134048111057
1151938733963
1221b90536415
13c84376c913
1466b8d845d7
15374843dc72
hex1f35e3d9d1

134048111057 has 8 divisors (see below), whose sum is σ = 153208603200. Its totient is φ = 114890309424.

The previous prime is 134048111047. The next prime is 134048111081. The reversal of 134048111057 is 750111840431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134048111057 - 26 = 134048110993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134048111047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 564707 + ... + 766152.

It is an arithmetic number, because the mean of its divisors is an integer number (19151075400).

Almost surely, 2134048111057 is an apocalyptic number.

It is an amenable number.

134048111057 is a deficient number, since it is larger than the sum of its proper divisors (19160492143).

134048111057 is a wasteful number, since it uses less digits than its factorization.

134048111057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1345255.

The product of its (nonzero) digits is 13440, while the sum is 35.

Adding to 134048111057 its reverse (750111840431), we get a palindrome (884159951488).

The spelling of 134048111057 in words is "one hundred thirty-four billion, forty-eight million, one hundred eleven thousand, fifty-seven".

Divisors: 1 7 14389 100723 1330859 9316013 19149730151 134048111057