1340481134141 has 4 divisors (see below), whose sum is σ = 1411032772800. Its totient is φ = 1269929495484.

The previous prime is 1340481134077. The next prime is 1340481134159. The reversal of 1340481134141 is 1414311840431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340481134141 - 2⁶ = 1340481134077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340481134341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35275819301 + ... + 35275819338.

It is an arithmetic number, because the mean of its divisors is an integer number (352758193200).

Almost surely, 2^{1340481134141} is an apocalyptic number.

It is an amenable number.

1340481134141 is a deficient number, since it is larger than the sum of its proper divisors (70551638659).

1340481134141 is an equidigital number, since it uses as much as digits as its factorization.

1340481134141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70551638658.

The product of its (nonzero) digits is 18432, while the sum is 35.

Adding to 1340481134141 its reverse (1414311840431), we get a palindrome (2754792974572).

The spelling of 1340481134141 in words is "one trillion, three hundred forty billion, four hundred eighty-one million, one hundred thirty-four thousand, one hundred forty-one".