Base | Representation |
---|---|
bin | 11000111110000000… |
… | …01010110111100101 |
3 | 1021121012221121000201 |
4 | 30133000022313211 |
5 | 204423142240401 |
6 | 10054100310501 |
7 | 653121650365 |
oct | 143700126745 |
9 | 37535847021 |
10 | 13405040101 |
11 | 5759883042 |
12 | 27213a2431 |
13 | 13582893bb |
14 | 9124829a5 |
15 | 536cadb01 |
hex | 31f00ade5 |
13405040101 has 2 divisors, whose sum is σ = 13405040102. Its totient is φ = 13405040100.
The previous prime is 13405040087. The next prime is 13405040149. The reversal of 13405040101 is 10104050431.
13405040101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13087131201 + 317908900 = 114399^2 + 17830^2 .
It is a cyclic number.
It is not a de Polignac number, because 13405040101 - 217 = 13404909029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405040191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702520050 + 6702520051.
It is an arithmetic number, because the mean of its divisors is an integer number (6702520051).
Almost surely, 213405040101 is an apocalyptic number.
It is an amenable number.
13405040101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405040101 is an equidigital number, since it uses as much as digits as its factorization.
13405040101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 13405040101 its reverse (10104050431), we get a palindrome (23509090532).
The spelling of 13405040101 in words is "thirteen billion, four hundred five million, forty thousand, one hundred one".
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