13405041521 has 2 divisors, whose sum is σ = 13405041522. Its totient is φ = 13405041520.

The previous prime is 13405041479. The next prime is 13405041523. The reversal of 13405041521 is 12514050431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12147346225 + 1257695296 = 110215^2 + 35464^2 .

It is an emirp because it is prime and its reverse (12514050431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13405041521 - 2¹⁰ = 13405040497 is a prime.

Together with 13405041523, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13405041523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702520760 + 6702520761.

It is an arithmetic number, because the mean of its divisors is an integer number (6702520761).

Almost surely, 2^13405041521 is an apocalyptic number.

It is an amenable number.

13405041521 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405041521 is an equidigital number, since it uses as much as digits as its factorization.

13405041521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 13405041521 its reverse (12514050431), we get a palindrome (25919091952).

It can be divided in two parts, 134050 and 41521, that added together give a palindrome (175571).

The spelling of 13405041521 in words is "thirteen billion, four hundred five million, forty-one thousand, five hundred twenty-one".