13405041523 has 2 divisors, whose sum is σ = 13405041524. Its totient is φ = 13405041522.

The previous prime is 13405041521. The next prime is 13405041527. The reversal of 13405041523 is 32514050431.

13405041523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13405041523 - 2¹ = 13405041521 is a prime.

It is a super-3 number, since 3×13405041523³ (a number of 31 digits) contains 333 as substring.

Together with 13405041521, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13405041491 and 13405041500.

It is not a weakly prime, because it can be changed into another prime (13405041521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702520761 + 6702520762.

It is an arithmetic number, because the mean of its divisors is an integer number (6702520762).

Almost surely, 2^13405041523 is an apocalyptic number.

13405041523 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405041523 is an equidigital number, since it uses as much as digits as its factorization.

13405041523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 13405041523 its reverse (32514050431), we get a palindrome (45919091954).

The spelling of 13405041523 in words is "thirteen billion, four hundred five million, forty-one thousand, five hundred twenty-three".