Base | Representation |
---|---|
bin | 11000111110000000… |
… | …01011001110010001 |
3 | 1021121012221200000111 |
4 | 30133000023032101 |
5 | 204423142312203 |
6 | 10054100321321 |
7 | 653121654541 |
oct | 143700131621 |
9 | 37535850014 |
10 | 13405041553 |
11 | 5759884142 |
12 | 27213a3241 |
13 | 1358289c67 |
14 | 912483321 |
15 | 536cae26d |
hex | 31f00b391 |
13405041553 has 4 divisors (see below), whose sum is σ = 13731993828. Its totient is φ = 13078089280.
The previous prime is 13405041547. The next prime is 13405041571. The reversal of 13405041553 is 35514050431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 236790544 + 13168251009 = 15388^2 + 114753^2 .
It is a cyclic number.
It is not a de Polignac number, because 13405041553 - 25 = 13405041521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13405041523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163476076 + ... + 163476157.
It is an arithmetic number, because the mean of its divisors is an integer number (3432998457).
Almost surely, 213405041553 is an apocalyptic number.
It is an amenable number.
13405041553 is a deficient number, since it is larger than the sum of its proper divisors (326952275).
13405041553 is an equidigital number, since it uses as much as digits as its factorization.
13405041553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 326952274.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 13405041553 its reverse (35514050431), we get a palindrome (48919091984).
The spelling of 13405041553 in words is "thirteen billion, four hundred five million, forty-one thousand, five hundred fifty-three".
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