13405216133 has 4 divisors (see below), whose sum is σ = 13405641600. Its totient is φ = 13404790668.

The previous prime is 13405216067. The next prime is 13405216169. The reversal of 13405216133 is 33161250431.

13405216133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13405216133 - 2¹⁴ = 13405199749 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13405216096 and 13405216105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13405216183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161333 + ... + 229866.

It is an arithmetic number, because the mean of its divisors is an integer number (3351410400).

Almost surely, 2^13405216133 is an apocalyptic number.

It is an amenable number.

13405216133 is a deficient number, since it is larger than the sum of its proper divisors (425467).

13405216133 is an equidigital number, since it uses as much as digits as its factorization.

13405216133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 425466.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 13405216133 its reverse (33161250431), we get a palindrome (46566466564).

The spelling of 13405216133 in words is "thirteen billion, four hundred five million, two hundred sixteen thousand, one hundred thirty-three".