Base | Representation |
---|---|
bin | 11000111110000001… |
… | …10101110110000111 |
3 | 1021121020021112111111 |
4 | 30133000311312013 |
5 | 204423213404020 |
6 | 10054104145451 |
7 | 653123312533 |
oct | 143700656607 |
9 | 37536245444 |
10 | 13405216135 |
11 | 5759993323 |
12 | 2721468287 |
13 | 135831b56c |
14 | 9124cabc3 |
15 | 536ce5d5a |
hex | 31f035d87 |
13405216135 has 4 divisors (see below), whose sum is σ = 16086259368. Its totient is φ = 10724172904.
The previous prime is 13405216067. The next prime is 13405216169. The reversal of 13405216135 is 53161250431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53161250431 = 19 ⋅2797960549.
It is a cyclic number.
It is not a de Polignac number, because 13405216135 - 215 = 13405183367 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13405216097 and 13405216106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340521609 + ... + 1340521618.
It is an arithmetic number, because the mean of its divisors is an integer number (4021564842).
Almost surely, 213405216135 is an apocalyptic number.
13405216135 is a deficient number, since it is larger than the sum of its proper divisors (2681043233).
13405216135 is an equidigital number, since it uses as much as digits as its factorization.
13405216135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2681043232.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13405216135 its reverse (53161250431), we get a palindrome (66566466566).
The spelling of 13405216135 in words is "thirteen billion, four hundred five million, two hundred sixteen thousand, one hundred thirty-five".
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