13405430540133 has 6 divisors (see below), whose sum is σ = 19363399669094. Its totient is φ = 8936953693416.

The previous prime is 13405430540113. The next prime is 13405430540179. The reversal of 13405430540133 is 33104503450431.

13405430540133 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 54 + 30 + 540 + 1 + 33 = 666.

It can be written as a sum of positive squares in only one way, i.e., 10998396202689 + 2407034337444 = 3316383^2 + 1551462^2 .

It is not a de Polignac number, because 13405430540133 - 2²⁰ = 13405429491557 is a prime.

It is a super-2 number, since 2×13405430540133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13405430540113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 744746141110 + ... + 744746141127.

Almost surely, 2^{13405430540133} is an apocalyptic number.

It is an amenable number.

13405430540133 is a deficient number, since it is larger than the sum of its proper divisors (5957969128961).

13405430540133 is a wasteful number, since it uses less digits than its factorization.

13405430540133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1489492282243 (or 1489492282240 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 36.

Adding to 13405430540133 its reverse (33104503450431), we get a palindrome (46509933990564).

The spelling of 13405430540133 in words is "thirteen trillion, four hundred five billion, four hundred thirty million, five hundred forty thousand, one hundred thirty-three".