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13405451 is a prime number
BaseRepresentation
bin110011001000…
…110100001011
3221020001211012
4303020310023
511412433301
61155154135
7221641643
oct63106413
927201735
1013405451
117626794
1245a594b
132a14927
141acd523
15129bebb
hexcc8d0b

13405451 has 2 divisors, whose sum is σ = 13405452. Its totient is φ = 13405450.

The previous prime is 13405429. The next prime is 13405459. The reversal of 13405451 is 15450431.

13405451 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13405451 - 210 = 13404427 is a prime.

It is a super-2 number, since 2×134054512 = 359412233026802, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13405459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702725 + 6702726.

It is an arithmetic number, because the mean of its divisors is an integer number (6702726).

Almost surely, 213405451 is an apocalyptic number.

13405451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405451 is an equidigital number, since it uses as much as digits as its factorization.

13405451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 13405451 is about 3661.3455177025. The cubic root of 13405451 is about 237.5529765479.

Adding to 13405451 its reverse (15450431), we get a palindrome (28855882).

The spelling of 13405451 in words is "thirteen million, four hundred five thousand, four hundred fifty-one".