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1340550145431 = 32721278573737
BaseRepresentation
bin10011100000011111000…
…000111110010110010111
311202011012020121021101100
4103200133000332112113
5133430421314123211
62503501254001143
7165565040140620
oct23403700762627
94664166537340
101340550145431
11477584677682
121979836461b3
139954b13b433
1448c50c42a47
1524d0dd7d156
hex1381f03e597

1340550145431 has 12 divisors (see below), whose sum is σ = 2212971668752. Its totient is φ = 766028654496.

The previous prime is 1340550145421. The next prime is 1340550145433. The reversal of 1340550145431 is 1345410550431.

1340550145431 is a `hidden beast` number, since 1 + 3 + 40 + 550 + 14 + 54 + 3 + 1 = 666.

It is not a de Polignac number, because 1340550145431 - 214 = 1340550129047 is a prime.

It is a super-2 number, since 2×13405501454312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340550145433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10639286806 + ... + 10639286931.

Almost surely, 21340550145431 is an apocalyptic number.

1340550145431 is a deficient number, since it is larger than the sum of its proper divisors (872421523321).

1340550145431 is a wasteful number, since it uses less digits than its factorization.

1340550145431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21278573750 (or 21278573747 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 1340550145431 its reverse (1345410550431), we get a palindrome (2685960695862).

The spelling of 1340550145431 in words is "one trillion, three hundred forty billion, five hundred fifty million, one hundred forty-five thousand, four hundred thirty-one".

Divisors: 1 3 7 9 21 63 21278573737 63835721211 148950016159 191507163633 446850048477 1340550145431