134055244121335 has 8 divisors (see below), whose sum is σ = 160866653111280. Its totient is φ = 107243955186624.

The previous prime is 134055244121333. The next prime is 134055244121387. The reversal of 134055244121335 is 533121442550431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134055244121335 - 2¹ = 134055244121333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134055244121291 and 134055244121300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134055244121333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27538702 + ... + 32038891.

It is an arithmetic number, because the mean of its divisors is an integer number (20108331638910).

Almost surely, 2^{134055244121335} is an apocalyptic number.

134055244121335 is a deficient number, since it is larger than the sum of its proper divisors (26811408989945).

134055244121335 is an equidigital number, since it uses as much as digits as its factorization.

134055244121335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60027617.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 134055244121335 its reverse (533121442550431), we get a palindrome (667176686671766).

The spelling of 134055244121335 in words is "one hundred thirty-four trillion, fifty-five billion, two hundred forty-four million, one hundred twenty-one thousand, three hundred thirty-five".