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1340621462071 is a prime number
BaseRepresentation
bin10011100000100011010…
…001000001101000110111
311202011101012210112102101
4103200203101001220313
5133431043043241241
62503512322322531
7165566564260063
oct23404321015067
94664335715371
101340621462071
11477610957951
121979a34b9447
139955cb4b328
1448c5a4c8aa3
1524d15268e31
hex13823441a37

1340621462071 has 2 divisors, whose sum is σ = 1340621462072. Its totient is φ = 1340621462070.

The previous prime is 1340621462041. The next prime is 1340621462083. The reversal of 1340621462071 is 1702641260431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340621462071 - 25 = 1340621462039 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1340621462071.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340621462041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670310731035 + 670310731036.

It is an arithmetic number, because the mean of its divisors is an integer number (670310731036).

Almost surely, 21340621462071 is an apocalyptic number.

1340621462071 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340621462071 is an equidigital number, since it uses as much as digits as its factorization.

1340621462071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 37.

The spelling of 1340621462071 in words is "one trillion, three hundred forty billion, six hundred twenty-one million, four hundred sixty-two thousand, seventy-one".