Base | Representation |
---|---|
bin | 111110011011011101… |
… | …0110001001000010111 |
3 | 110211001020122000002201 |
4 | 1330312322301020113 |
5 | 4144031213031211 |
6 | 141331101545331 |
7 | 12454156525021 |
oct | 1746672611027 |
9 | 424036560081 |
10 | 134065361431 |
11 | 51947446371 |
12 | 21b96275247 |
13 | c8471cc641 |
14 | 66bb395011 |
15 | 3749bea0c1 |
hex | 1f36eb1217 |
134065361431 has 4 divisors (see below), whose sum is σ = 134089605864. Its totient is φ = 134041117000.
The previous prime is 134065361401. The next prime is 134065361467. The reversal of 134065361431 is 134163560431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 134163560431 = 17 ⋅7891974143.
It is a cyclic number.
It is not a de Polignac number, because 134065361431 - 217 = 134065230359 is a prime.
It is a super-2 number, since 2×1340653614312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134065361401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12113920 + ... + 12124981.
It is an arithmetic number, because the mean of its divisors is an integer number (33522401466).
Almost surely, 2134065361431 is an apocalyptic number.
134065361431 is a deficient number, since it is larger than the sum of its proper divisors (24244433).
134065361431 is an equidigital number, since it uses as much as digits as its factorization.
134065361431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24244432.
The product of its (nonzero) digits is 77760, while the sum is 37.
The spelling of 134065361431 in words is "one hundred thirty-four billion, sixty-five million, three hundred sixty-one thousand, four hundred thirty-one".
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