13410012520435 has 4 divisors (see below), whose sum is σ = 16092015024528. Its totient is φ = 10728010016344.

The previous prime is 13410012520433. The next prime is 13410012520477. The reversal of 13410012520435 is 53402521001431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13410012520435 - 2¹ = 13410012520433 is a prime.

It is a super-2 number, since 2×13410012520435² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13410012520397 and 13410012520406.

It is not an unprimeable number, because it can be changed into a prime (13410012520433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1341001252039 + ... + 1341001252048.

It is an arithmetic number, because the mean of its divisors is an integer number (4023003756132).

Almost surely, 2^{13410012520435} is an apocalyptic number.

13410012520435 is a deficient number, since it is larger than the sum of its proper divisors (2682002504093).

13410012520435 is an equidigital number, since it uses as much as digits as its factorization.

13410012520435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2682002504092.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13410012520435 its reverse (53402521001431), we get a palindrome (66812533521866).

The spelling of 13410012520435 in words is "thirteen trillion, four hundred ten billion, twelve million, five hundred twenty thousand, four hundred thirty-five".