1341001333 has 4 divisors (see below), whose sum is σ = 1532572960. Its totient is φ = 1149429708.

The previous prime is 1341001331. The next prime is 1341001339. The reversal of 1341001333 is 3331001431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3331001431 = 46307 ⋅71933.

It is not a de Polignac number, because 1341001333 - 2¹ = 1341001331 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1341001333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341001331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95785803 + ... + 95785816.

It is an arithmetic number, because the mean of its divisors is an integer number (383143240).

Almost surely, 2^1341001333 is an apocalyptic number.

It is an amenable number.

1341001333 is a deficient number, since it is larger than the sum of its proper divisors (191571627).

1341001333 is an equidigital number, since it uses as much as digits as its factorization.

1341001333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191571626.

The product of its (nonzero) digits is 324, while the sum is 19.

The square root of 1341001333 is about 36619.6850477991. The cubic root of 1341001333 is about 1102.7483158538.

Adding to 1341001333 its reverse (3331001431), we get a palindrome (4672002764).

The spelling of 1341001333 in words is "one billion, three hundred forty-one million, one thousand, three hundred thirty-three".