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13410021010453 is a prime number
BaseRepresentation
bin1100001100100100001110…
…0010011110110000010101
31202110222121102100222022121
43003021003202132300111
53224202210334313303
644304251213455541
72552561551602334
oct303110342366025
952428542328277
1013410021010453
114300181297611
121606b50aa15b1
1376373745c232
14345097059d1b
15183c5abdd9bd
hexc324389ec15

13410021010453 has 2 divisors, whose sum is σ = 13410021010454. Its totient is φ = 13410021010452.

The previous prime is 13410021010447. The next prime is 13410021010459. The reversal of 13410021010453 is 35401012001431.

It is a balanced prime because it is at equal distance from previous prime (13410021010447) and next prime (13410021010459).

It can be written as a sum of positive squares in only one way, i.e., 7055069075044 + 6354951935409 = 2656138^2 + 2520903^2 .

It is a cyclic number.

It is not a de Polignac number, because 13410021010453 - 29 = 13410021009941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13410021010459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705010505226 + 6705010505227.

It is an arithmetic number, because the mean of its divisors is an integer number (6705010505227).

Almost surely, 213410021010453 is an apocalyptic number.

It is an amenable number.

13410021010453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410021010453 is an equidigital number, since it uses as much as digits as its factorization.

13410021010453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13410021010453 its reverse (35401012001431), we get a palindrome (48811033011884).

The spelling of 13410021010453 in words is "thirteen trillion, four hundred ten billion, twenty-one million, ten thousand, four hundred fifty-three".