Base | Representation |
---|---|
bin | 11000111110100111… |
… | …00011010011111111 |
3 | 1021121120111201122122 |
4 | 30133103203103333 |
5 | 204430442332314 |
6 | 10054401233155 |
7 | 653213101364 |
oct | 143723432377 |
9 | 37546451578 |
10 | 13410120959 |
11 | 57617333a4 |
12 | 27230327bb |
13 | 1359347c21 |
14 | 91300646b |
15 | 53746428e |
hex | 31f4e34ff |
13410120959 has 2 divisors, whose sum is σ = 13410120960. Its totient is φ = 13410120958.
The previous prime is 13410120949. The next prime is 13410121007. The reversal of 13410120959 is 95902101431.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (95902101431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13410120959 - 24 = 13410120943 is a prime.
It is a super-2 number, since 2×134101209592 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13410120949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705060479 + 6705060480.
It is an arithmetic number, because the mean of its divisors is an integer number (6705060480).
Almost surely, 213410120959 is an apocalyptic number.
13410120959 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410120959 is an equidigital number, since it uses as much as digits as its factorization.
13410120959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 13410120959 in words is "thirteen billion, four hundred ten million, one hundred twenty thousand, nine hundred fifty-nine".
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