13410213000001 has 2 divisors, whose sum is σ = 13410213000002. Its totient is φ = 13410213000000.

The previous prime is 13410212999983. The next prime is 13410213000007. The reversal of 13410213000001 is 10000031201431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13309355943601 + 100857056400 = 3648199^2 + 317580^2 .

It is a cyclic number.

It is not a de Polignac number, because 13410213000001 - 2⁷ = 13410212999873 is a prime.

It is not a weakly prime, because it can be changed into another prime (13410213000007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705106500000 + 6705106500001.

It is an arithmetic number, because the mean of its divisors is an integer number (6705106500001).

Almost surely, 2^{13410213000001} is an apocalyptic number.

It is an amenable number.

13410213000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410213000001 is an equidigital number, since it uses as much as digits as its factorization.

13410213000001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13410213000001 its reverse (10000031201431), we get a palindrome (23410244201432).

The spelling of 13410213000001 in words is "thirteen trillion, four hundred ten billion, two hundred thirteen million, one", and thus it is an aban number.