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134102421200000 = 27551130477823
BaseRepresentation
bin11110011111011100100111…
…001011011101110010000000
3122120211001210022021000221202
4132133130213023131302000
5120034113224311400000
61153113445105440332
740150403003434331
oct3637344713356200
9576731708230852
10134102421200000
11398025767a7330
1213059b456400a8
1359a9a5b68c676
14251883dd3a288
1510784a2100dd5
hex79f7272ddc80

134102421200000 has 192 divisors, whose sum is σ = 364281924464640. Its totient is φ = 48764515200000.

The previous prime is 134102421199993. The next prime is 134102421200087. The reversal of 134102421200000 is 2124201431.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10838912 + ... + 19638911.

It is an arithmetic number, because the mean of its divisors is an integer number (1897301689920).

Almost surely, 2134102421200000 is an apocalyptic number.

134102421200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134102421200000 is an abundant number, since it is smaller than the sum of its proper divisors (230179503264640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134102421200000 is an frugal number, since it uses more digits than its factorization.

134102421200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30477873 (or 30477841 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 134102421200000 its reverse (2124201431), we get a palindrome (134104545401431).

The spelling of 134102421200000 in words is "one hundred thirty-four trillion, one hundred two billion, four hundred twenty-one million, two hundred thousand".