13410340043140 has 24 divisors (see below), whose sum is σ = 28170199229760. Its totient is φ = 5362519800288.

The previous prime is 13410340043137. The next prime is 13410340043143. The reversal of 13410340043140 is 4134004301431.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (13410340043137) and next prime (13410340043143).

It is a super-3 number, since 3×13410340043140³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13410340043099 and 13410340043108.

It is not an unprimeable number, because it can be changed into a prime (13410340043143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100945522 + ... + 101078281.

It is an arithmetic number, because the mean of its divisors is an integer number (1173758301240).

Almost surely, 2^{13410340043140} is an apocalyptic number.

13410340043140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13410340043140 is an abundant number, since it is smaller than the sum of its proper divisors (14759859186620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13410340043140 is a wasteful number, since it uses less digits than its factorization.

13410340043140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202027131 (or 202027129 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 13410340043140 its reverse (4134004301431), we get a palindrome (17544344344571).

The spelling of 13410340043140 in words is "thirteen trillion, four hundred ten billion, three hundred forty million, forty-three thousand, one hundred forty".