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13410433134143 is a prime number
BaseRepresentation
bin1100001100100101110000…
…0110100110111000111111
31202111000200010212000201222
43003021130012212320333
53224204031340243033
644304400135023555
72552605014600203
oct303113406467077
952430603760658
1013410433134143
114300372993201
121607046b0abbb
137637a1956bc6
143450d5a98b03
15183c81e99598
hexc325c1a6e3f

13410433134143 has 2 divisors, whose sum is σ = 13410433134144. Its totient is φ = 13410433134142.

The previous prime is 13410433134053. The next prime is 13410433134149. The reversal of 13410433134143 is 34143133401431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13410433134143 - 216 = 13410433068607 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13410433134149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705216567071 + 6705216567072.

It is an arithmetic number, because the mean of its divisors is an integer number (6705216567072).

Almost surely, 213410433134143 is an apocalyptic number.

13410433134143 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410433134143 is an equidigital number, since it uses as much as digits as its factorization.

13410433134143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 13410433134143 its reverse (34143133401431), we get a palindrome (47553566535574).

The spelling of 13410433134143 in words is "thirteen trillion, four hundred ten billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred forty-three".