Base | Representation |
---|---|
bin | 1100001100100101110000… |
… | …0110100110111000111111 |
3 | 1202111000200010212000201222 |
4 | 3003021130012212320333 |
5 | 3224204031340243033 |
6 | 44304400135023555 |
7 | 2552605014600203 |
oct | 303113406467077 |
9 | 52430603760658 |
10 | 13410433134143 |
11 | 4300372993201 |
12 | 1607046b0abbb |
13 | 7637a1956bc6 |
14 | 3450d5a98b03 |
15 | 183c81e99598 |
hex | c325c1a6e3f |
13410433134143 has 2 divisors, whose sum is σ = 13410433134144. Its totient is φ = 13410433134142.
The previous prime is 13410433134053. The next prime is 13410433134149. The reversal of 13410433134143 is 34143133401431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13410433134143 - 216 = 13410433068607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13410433134149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705216567071 + 6705216567072.
It is an arithmetic number, because the mean of its divisors is an integer number (6705216567072).
Almost surely, 213410433134143 is an apocalyptic number.
13410433134143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410433134143 is an equidigital number, since it uses as much as digits as its factorization.
13410433134143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 13410433134143 its reverse (34143133401431), we get a palindrome (47553566535574).
The spelling of 13410433134143 in words is "thirteen trillion, four hundred ten billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred forty-three".
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