Base | Representation |
---|---|
bin | 1100001100100101110101… |
… | …0111110100010000000111 |
3 | 1202111000201121220120220221 |
4 | 3003021131113310100013 |
5 | 3224204102313010120 |
6 | 44304402215205211 |
7 | 2552605363543402 |
oct | 303113527642007 |
9 | 52430647816827 |
10 | 13410454422535 |
11 | 4300383a03515 |
12 | 1607052076807 |
13 | 7637a619b8a1 |
14 | 3450d883ad39 |
15 | 183c83ca20aa |
hex | c325d5f4407 |
13410454422535 has 16 divisors (see below), whose sum is σ = 16109961993216. Its totient is φ = 10716756012288.
The previous prime is 13410454422527. The next prime is 13410454422577. The reversal of 13410454422535 is 53522445401431.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 13410454422535 - 23 = 13410454422527 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13410454422491 and 13410454422500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30032314 + ... + 30475576.
It is an arithmetic number, because the mean of its divisors is an integer number (1006872624576).
Almost surely, 213410454422535 is an apocalyptic number.
13410454422535 is a deficient number, since it is larger than the sum of its proper divisors (2699507570681).
13410454422535 is a wasteful number, since it uses less digits than its factorization.
13410454422535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 449802.
The product of its (nonzero) digits is 1152000, while the sum is 43.
Adding to 13410454422535 its reverse (53522445401431), we get a palindrome (66932899823966).
The spelling of 13410454422535 in words is "thirteen trillion, four hundred ten billion, four hundred fifty-four million, four hundred twenty-two thousand, five hundred thirty-five".
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