Base | Representation |
---|---|
bin | 11000111110101001… |
… | …10110111100001101 |
3 | 1021121121011010112101 |
4 | 30133110312330031 |
5 | 204431034313001 |
6 | 10054412435101 |
7 | 653216026141 |
oct | 143724667415 |
9 | 37547133471 |
10 | 13410463501 |
11 | 5761947796 |
12 | 2723178a91 |
13 | 1359437b06 |
14 | 913095221 |
15 | 5374d0a01 |
hex | 31f536f0d |
13410463501 has 2 divisors, whose sum is σ = 13410463502. Its totient is φ = 13410463500.
The previous prime is 13410463499. The next prime is 13410463519. The reversal of 13410463501 is 10536401431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10115129476 + 3295334025 = 100574^2 + 57405^2 .
It is a cyclic number.
It is not a de Polignac number, because 13410463501 - 21 = 13410463499 is a prime.
Together with 13410463499, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13410463501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13410463201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705231750 + 6705231751.
It is an arithmetic number, because the mean of its divisors is an integer number (6705231751).
Almost surely, 213410463501 is an apocalyptic number.
It is an amenable number.
13410463501 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410463501 is an equidigital number, since it uses as much as digits as its factorization.
13410463501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13410463501 its reverse (10536401431), we get a palindrome (23946864932).
The spelling of 13410463501 in words is "thirteen billion, four hundred ten million, four hundred sixty-three thousand, five hundred one".
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