Base | Representation |
---|---|
bin | 11000111110110000… |
… | …01101011011001111 |
3 | 1021121122210202122112 |
4 | 30133120031123033 |
5 | 204431300421111 |
6 | 10054443334235 |
7 | 653226345353 |
oct | 143730153317 |
9 | 37548722575 |
10 | 13411342031 |
11 | 576239784a |
12 | 272352137b |
13 | 1359684959 |
14 | 913243463 |
15 | 537605e8b |
hex | 31f60d6cf |
13411342031 has 4 divisors (see below), whose sum is σ = 13416977064. Its totient is φ = 13405707000.
The previous prime is 13411342027. The next prime is 13411342039. The reversal of 13411342031 is 13024311431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13411342031 - 22 = 13411342027 is a prime.
It is a super-2 number, since 2×134113420312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13411341988 and 13411342006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13411342039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2813945 + ... + 2818706.
It is an arithmetic number, because the mean of its divisors is an integer number (3354244266).
Almost surely, 213411342031 is an apocalyptic number.
13411342031 is a deficient number, since it is larger than the sum of its proper divisors (5635033).
13411342031 is an equidigital number, since it uses as much as digits as its factorization.
13411342031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5635032.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13411342031 its reverse (13024311431), we get a palindrome (26435653462).
The spelling of 13411342031 in words is "thirteen billion, four hundred eleven million, three hundred forty-two thousand, thirty-one".
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