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13411342031 = 23815632651
BaseRepresentation
bin11000111110110000…
…01101011011001111
31021121122210202122112
430133120031123033
5204431300421111
610054443334235
7653226345353
oct143730153317
937548722575
1013411342031
11576239784a
12272352137b
131359684959
14913243463
15537605e8b
hex31f60d6cf

13411342031 has 4 divisors (see below), whose sum is σ = 13416977064. Its totient is φ = 13405707000.

The previous prime is 13411342027. The next prime is 13411342039. The reversal of 13411342031 is 13024311431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13411342031 - 22 = 13411342027 is a prime.

It is a super-2 number, since 2×134113420312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13411341988 and 13411342006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411342039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2813945 + ... + 2818706.

It is an arithmetic number, because the mean of its divisors is an integer number (3354244266).

Almost surely, 213411342031 is an apocalyptic number.

13411342031 is a deficient number, since it is larger than the sum of its proper divisors (5635033).

13411342031 is an equidigital number, since it uses as much as digits as its factorization.

13411342031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5635032.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13411342031 its reverse (13024311431), we get a palindrome (26435653462).

The spelling of 13411342031 in words is "thirteen billion, four hundred eleven million, three hundred forty-two thousand, thirty-one".

Divisors: 1 2381 5632651 13411342031