Base | Representation |
---|---|
bin | 1100001100101001011010… |
… | …0001010011010000010011 |
3 | 1202111010012110001001020122 |
4 | 3003022112201103100103 |
5 | 3224213033240211011 |
6 | 44305041305300455 |
7 | 2552641215236456 |
oct | 303122641232023 |
9 | 52433173031218 |
10 | 13411413210131 |
11 | 4300826138862 |
12 | 160727b19472b |
13 | 7638c9a09421 |
14 | 345189cdb49d |
15 | 183cdd0423db |
hex | c3296853413 |
13411413210131 has 2 divisors, whose sum is σ = 13411413210132. Its totient is φ = 13411413210130.
The previous prime is 13411413210061. The next prime is 13411413210263. The reversal of 13411413210131 is 13101231411431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411413210131 - 222 = 13411409015827 is a prime.
It is a super-2 number, since 2×134114132101312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13411413210131.
It is not a weakly prime, because it can be changed into another prime (13411413210331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705706605065 + 6705706605066.
It is an arithmetic number, because the mean of its divisors is an integer number (6705706605066).
Almost surely, 213411413210131 is an apocalyptic number.
13411413210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411413210131 is an equidigital number, since it uses as much as digits as its factorization.
13411413210131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 26.
Adding to 13411413210131 its reverse (13101231411431), we get a palindrome (26512644621562).
The spelling of 13411413210131 in words is "thirteen trillion, four hundred eleven billion, four hundred thirteen million, two hundred ten thousand, one hundred thirty-one".
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